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Answer. Using gas laws: \dfrac {\text {P}_1 {\text {V}_1}} {\text {T}_1} T1P1V1 = \dfrac {\text {P}_2 {\text {V}_2}} {\text {T}_2} T2P2V2. Substituting the values: \dfrac {70 \times 760} {300} 30070 × 760 = \dfrac {76 \times {\text {V}_2}} {273} 27376 × V2. Therefore:
Get solutions of ICSE Class 9 Concise Chemistry Selina Chapter 7: Study of Gas Laws. Clear your Chemistry doubts instantly & get more marks in Chemistry exam easily. Master the concepts with our detailed explanations & solutions.
ICSE Selina Solution for Class 9 Chemistry Chapter 7 covers all the exercise questions and numerical problems provided in the Selina publishers ICSE Class 9 Chemistry textbook. This solution has different varieties of questions that will help you build problem-solving capacity.
Explore Concise Chemistry Part I - Selina Solutions for Class 9 Chemistry Chapter 7: Study of Gas Laws Access free solved exercises to boost your understanding at TopperLearning now!
Get free Viraf J. Dalal Solutions for Class 9 Simplified ICSE Chemistry Chapter 7 Study Of Gas Laws solved by experts. Available here are Chapter 7 - Study Of Gas Laws Exercises Questions with Solutions and detail explanation for your practice before the examination.
21 wrz 2023 · Study of Gas Laws Class-9 Chemistry Concise Solutions. Page-133. Question 1. Convert : (i) 273°C to kelvin. (ii) 293 K to °C. Answer: (i) Kelvin = °C + 273 = 273 + 273 = 546 K. (ii) °C = Kelvin – 273 = 293 – 273 = 20°C. Question 2.
24 sie 2018 · What do you understand by gas? Solution: The state of matter in which inter-particle attraction is weak and inter-particle space is so large that the particles become completely free to move randomly in the entire available space, is known as gas. Question 2. Give the assumptions of the kinetic molecular theory. Solution:
