Search results
Polega to na spojrzeniu na równanie i dostosowaniu współczynników, aby uzyskać tę samą liczbę atomów każdego rodzaju po obu stronach równania. Najlepsze do: prostych równań z małą liczbą atomów.
Najpierw ustawiamy wszystkie współczynniki na zmienne a, b, c, d, ... a C 3 H 6 + b KMnO 4 + c H 2 O = d C 2 H 4 (OH) 2 + e MnO 2 + f KOH Teraz zapisujemy równania algebraiczne bilansujące każdy atom:
O jest zrównoważony: 5 atomów w odczynnikach i 5 atomów w produktach. All atoms are now balanced and the whole equation is fully balanced: C 3 H 6 + KMnO 4 + H 2 O = C 3 H 5 (OH) 2 + KOH + MnO 2
Phản ứng propilen + KMnO 4 hay C 3 H 6 + KMnO 4 tạo ra C 3 H 6 O 2 thuộc loại phản ứng oxi hóa không hoàn toàn đã được cân bằng chính xác và chi tiết nhất.
Let's balance this equation using the algebraic method. First, we set all coefficients to variables a, b, c, d, ... Please tell about this free chemistry software to your friends! Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below.
Solved and balanced chemical equation 3 C3H6 + 4 KMnO4 + 2 H2O → 3 C3H6O2 + 4 MnO2 + 4 KOH with completed products. Application for completing products and balancing equations.
Balance the reaction of C3H6O + KMnO4 + H2O = CH3COOH + KOH + MnO2 using this chemical equation balancer!
