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x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history ...
The derivative of arctan x is 1/(1+x 2). i.e., d/dx(arctan x) = 1/(1+x 2). This also can be written as d/dx(tan -1 x) = 1/(1+x 2 ). How to Prove Derivative of Arctan Formula?
Learn how to solve differential calculus problems step by step online. Find the derivative of arctan(x). Taking the derivative of arctangent. The derivative of the linear function is equal to 1.
What is the derivative of the arctangent function of x? The derivative of the arctangent function of x is equal to 1 divided by (1+x 2)
Calculator solves the derivative of a function f(x, y(x)..) or the derivative of an implicit function, along with a display of the rules used to calculate the derivative, including constant, sum, difference, constant multiple, product, power, reciprocal, quotient, and chain rules
