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The stoichiometric mixture for a gasoline engine is the ideal ratio of air to fuel that burns all fuel with no excess air. For gasoline fuel, the stoichiometric air–fuel mixture is about 14.7:1 [1] i.e. for every one gram of fuel, 14.7 grams of air are required.
The ideal (theoretical) air fuel ratio, for a complete combustion, is called stoichiometric air fuel ratio. For a gasoline (petrol) engine, the stoichiometric air fuel ratio is around 14.7:1. This means that, in order to burn completely 1 kg of fuel, we need 14.7 kg of air. The combustion is possible even is the AFR is different than ...
Stoichiometric air/fuel ratio (SAFR) or theoretical air/fuel ratio is the amount of air required for complete combustion of fuel which is calculated from the equation of stoichiometry of air/fuel reaction. The equivalence ratio (φ) is widely used to define the air/fuel quality in engines.
23 lip 2024 · The minimum amount of air needed for complete combustion is known as theoretical or stoichiometric air. That is the quantity of air used when calculating the stoichiometric air-fuel ratio. The general formula for the complete combustion of a hydrocarbon fuel with theoretical air is:
The stoichiometric air-fuel ratio represents the ideal balance at which complete combustion occurs, resulting in neither excess oxygen nor unburned fuel. Achieving this ratio is crucial for minimizing emissions and maximizing combustion efficiency.
The mean effective pressure peaks at slightly rich stoichiometry (between φ = 1 and φ = 1.2). However, the fuel conversion efficiency decreases as the mixture is enriched above the stoichiometry (φ > 1) because part of the fuel is left after the combustion.
When all the fuel is combined with all the free oxygen, typically within a vehicle’s combustion chamber, the reaction is chemically balanced and this air–fuel ratio is a stoichiometric relationship. The air–fuel ratio is an important measure for anti-pollution and performance tuning reasons.
