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21 lip 2023 · Show that the minimum muzzle velocity required to hit the plane is √v2 +2gh at an angle tan−1(√2ghv) II.
Velocity at any héight: From the equation v 2 = u 2 – 2gh we get, v = ±\(\sqrt{u^2-2 g h}\). Positive (+) sign is applicable for upward motion and negative (-) sign is applicable for downward motion.
5 sie 2022 · In summary, according to the conversation, the formula for V^2=u^2+2gh is used to find the velocity of an object after colliding with another object. The terms u, g, and h represent initial velocity, gravitational acceleration, and the height of the object, respectively.
K = U means you end up with the equation that you already wrote in your post title: v2 = 2 gh. If you plot v2 on the y-axis, and h on the x-axis, your linear slope y/x will equal roughly 2 g. That's linear, which is what you got.
A free falling object from a height #h# reaches the ground with a velocity #v# given by the kinematic equation #v^2-u^2=2gh# If the object is just dropped we have
