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16 sie 2010 · I'm trying to list the latest destination (MAX departure time) for each train in a table, for example: Train Dest Time 1 HK 10:00 1 SH 12:00 1 SZ 14:00 2 HK 13:00 2 SH 09:00 2 SZ 07:00. The desired result should be: Train Dest Time 1 SZ 14:00 2 HK 13:00. I have tried using.
24 sie 2012 · You can join against a subquery that pulls the MAX(Group) and Age. This method is portable across most RDBMS. SELECT t1.* FROM yourTable t1 INNER JOIN ( SELECT `Group`, MAX(Age) AS max_age FROM yourTable GROUP BY `Group` ) t2 ON t1.`Group` = t2.`Group` AND t1.Age = t2.max_age;
16 maj 2024 · In this page we are discussing, how the GROUP BY clause along with the SQL MAX () can be used to find the maximum value of a column over each group. Example: Sample table: agents.
The GROUP BY statement groups rows that have the same values into summary rows, like "find the number of customers in each country". The GROUP BY statement is often used with aggregate functions ( COUNT() , MAX() , MIN() , SUM() , AVG() ) to group the result-set by one or more columns.
29 paź 2013 · SELECT MAX([UpdateTime]) AS value. from. (. SELECT [UpdateTime] FROM [MyTable] group by [UpdateTime] ) as t. The inserts to this table are in chunks of 50,000 rows with the same date. So I thought grouping by might ease the MAX calculation.
I have a table with the following schema, and I need to define a query that can group data based on intervals of time (Ex. records per minute) and then provide the sum of the changes to the SnapShotValue since the previous group.
There are a few ways that you can solve this. You can use a subquery to apply the aggregate function to return the max(LAST_UPDATE_DATE_TIME) for each SCHOOL_CODE:
