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  1. DISTINCT keyword is supposed to be applied to all the columns in the select query and not just to the column next to which DISTINCT keyword is written. So, basically, it means that every row returned in the result will be unique in terms of the combination of the select query columns.

  2. 10 kwi 2011 · How can I use the DISTINCT clause with WHERE? For example: SELECT * FROM table WHERE DISTINCT email; -- email is a column name I want to select all columns from a table with distinct email addres...

  3. 10 wrz 2008 · 11. If your DBMS doesn't support distinct with multiple columns like this: select distinct(col1, col2) from table. Multi select in general can be executed safely as follows: select distinct * from (select col1, col2 from table ) as x. As this can work on most of the DBMS and this is expected to be faster than group by solution as you are ...

  4. Use DISTINCT to remove duplicate GROUPING SETS from the GROUP BY clause. In a completely silly example using GROUPING SETS() in general (or the special grouping sets ROLLUP() or CUBE() in particular), you could use DISTINCT in order to remove the duplicate values produced by the grouping sets again: SELECT DISTINCT actors.

  5. 10 paź 2008 · 17. If you want distinct values from only two fields, plus return other fields with them, then the other fields must have some kind of aggregation on them (sum, min, max, etc.), and the two columns you want distinct must appear in the group by clause. Otherwise, it's just as Decker says.

  6. 19 lut 2017 · Then at the end you put the distinct column to filter and you only group it with that last distinct column. This will bring you the maximum ID with the correspondent data, you can use min or any other functions and you replicate that function to the sub-queries.

  7. 60. The simplest solution would be to use a subquery for finding the minimum ID matching your query. In the subquery you use GROUP BY instead of DISTINCT: SELECT * FROM [TestData] WHERE [ID] IN (. SELECT MIN([ID]) FROM [TestData] WHERE [SKU] LIKE 'FOO-%'. GROUP BY [PRODUCT] ) edited Mar 28, 2012 at 8:22.

  8. 29 maj 2018 · Another possibility to get unique strings from STRING_AGG would be to perform these three steps after fetching the comma separated string: Example: from (SELECT distinct 1 single_key, value. FROM STRING_SPLIT(STRING_AGG(CAST(customer_division as VARCHAR(MAX)), ','), ',')) q group by single_key) as customer_division.

  9. 5 kwi 2019 · SELECT DISTINCT my_col, count(*) OVER (PARTITION BY my_col ORDER BY my_col) AS num_rows FROM my_tbl Using this OVER based approach is of course optional. In the above SQL, I found specifying DISTINCT and ORDER BY to be necessary. Caution: As per the docs, using GROUP BY may be more efficient.

  10. Count(DISTINCT program_name) AS [Count], FROM cm_production. WHERE push_number = @push_number. GROUP BY program_type. DISTINCT COUNT(*) will return a row for each unique count. What you want is COUNT(DISTINCT <expression>): evaluates expression for each row in a group and returns the number of unique, non-null values.

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