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  1. 24 sie 2020 · Using Luau: math.round(number*100)/100 or math.floor(value*100)/100. Using just Lua: math.floor(value*100)/100 (There is no math.round in vanilla lua)

  2. 11 lut 2022 · print(math.round(number * 100)/100) Without math: print(string.format("%.2f", number))

  3. 2 wrz 2021 · so how do I round a decimal to a specific number of decimal places? You could do something like this: return math.round(x / mult) * mult. It will round to the nearest mult number (kinda misnamed variable). For instance, to round in 0.01 increments: You can use this to round to larger numbers too: Thank you so much, it worked. Have a nice day!

  4. 27 maj 2024 · 📌 Links:Download Roblox Studio: https://create.roblox.comDiscord Server: https://discord.gg/v9rsEjzwHURoblox Group: https://www.roblox.com/groups/14588047/E...

  5. 8 sty 2017 · Given any number of the sort 78.689 or 1.12 for instance, what I'm looking for is to programmatically round the number to the nearest tenth place after the decimal.

  6. Returns the integer with the smallest difference between it and the given number. For example, the value 5.8 returns 6. For values like 0.5 that are equidistant to two integers, the value with the greater difference between it and zero is chosen. In other words, the function "rounds away from zero" such that 0.5 rounds to 1 and -0.5 rounds to -1.

  7. 7 lip 2021 · This way, when the number’s decimal is larger or equal to/than 0.5, it’ll round to the larger number, and when smaller, to the same number without (the Integer). Both ways (math.round then floor, or floor+0.5) should work

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