Search results
How do you evaluate and simplify \displaystyle{64}^{{-\frac{{2}}{{3}}}} ? https://socratic.org/questions/how-do-you-evaluate-and-simplify-64-2-3 See a solution process below: Explanation: First, rewrite the expression as: \displaystyle{64}^{{{\left(\frac{{1}}{{3}}\times-{2}\right)}}} Using this rule of exponents we can rewrite this as: ...
Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.
x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)
Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
64 2/3 may seem difficult to calculate at first but really boils down to two simple steps. This is because 64 2/3 = (64 1/3 ) 2 . This shows we can first do the operation inside of the brackets, followed by the outside operation, to obtain the answer. 64 to the power of a third is equal to the cube root of 64.
64^2/3. Simplify the rational exponent: 64 2 / 3. Analyze Fractional Exponent: a b / c = (c √ a) b. Take the c th root of a Then raise that to the power of b. In this case, a = 64, b = 2, and c = 3. Evaluate the 3 rd root of 64: 3 √ 64 = 4 since 4 3 = 64 as seen in our Exponent Lesson. Raise this value to the power of 2: Therefore, we can ...
11 mar 2017 · 64^(2/3) = 16 Notice that: 64 =2^6 Hence 64^(2/3) = (2^6)^(2/3) Using the rule of indices: (a^m)^n = a^(mxxn) 64^(2/3) = 2^(6xx2/3) = 2^(2xx2) = 2^4 = 16
