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We can compute Elastic potential energy by using fundamental formula as below: Elastic potential energy = force displacement. It is computed as the work done to stretch the spring which depends on the spring constant k and the displacement stretched. According to Hooke’s law, the force applied to stretch the spring is directly proportional to ...
Question 2: Give two examples of potential energy. Answer 2: The food which we consume contains potential energy. As our body digests this energy, it offers us the needed energy for bodily functions. Further, tree branches contain this energy as they can fall to the ground. Share with friends.
Elastic Potential Energy. As the name signifies, every object that behaves like an elastic or spring is a source of elastic potential energy. The best examples are rubber bands, springs etc. These elastic objects follow the Hooke’s Law. The stretching and compressing of elastic items lead to storage of energy in the form of Elastic Potential ...
In the figure, x is the displacement from the equilibrium position. When we pull the spring to a displacement of x as shown in the figure, the work done by the spring is : W = 0 ∫ xm Fdx = -∫kx dx = -k (x m) 2 /2. The work done by pulling force F p is : Fp = k (x m) 2 / 2. The work done by the pulling force F p is in positive as it has ...
(a) What is the spring constant? (b) The stone is pushed down an additional $$30.0 \,cm$$ and released. What is the elastic potential energy of the compressed spring just before that release? (c) What is the change in the gravitational potential energy of the stoneEarth system when the stone moves from the release point to its maximum height?
Click here:point_up_2:to get an answer to your question :writing_hand:two blocks of masses m and 3 m are placed on a frictionless horizontal surface 2
Show that the elastic force of a spring is a conservative force.Hence write an expression for the potential energy of an elastic stretch of spray. View Solution Q 2
Besides, the unit of measure for potential energy is Joule (J). Elastic Potential Energy Formula. F = K × x. PE = 0.5 k × \(x^2\) Derivation of the Formula. F = force of the object K = spring constant x = force proportional to the length of compression or stretch. Solved Example on Potential Energy Formula
Assertion (A) : The elastic potential energy of a spring increases when it is elongated and decreases when it is compressed. Reason (R) : Work done on spring is stored in it as elastic potential energy. When a spring is stretched by 2 cm, it stores 100 J of energy. If it is stretched further by 2 cm, the stored energy will be increased by.
Solution. Verified by Toppr. Correct option is B. decreases. Work done by a coil spring is given by, W = 1 2 k X 2. where k is the spring constant / stiffness. X is the extension or compression produced. This work done is stored in spring as elastic potential energy (PE) when the spring is compressed and hence elastic potential energy decreases.
