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15x^{2}-26x+8=0 All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
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Solve Using the Quadratic Formula 15x^2+26x+8=0. 15x2 + 26x + 8 = 0 15 x 2 + 26 x + 8 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 15 a = 15, b = 26 b = 26, and c = 8 c = 8 into the quadratic formula and solve for x x.
Step by step solution : Step 1 : Equation at the end of step 1 : ((3•5x2) - 26x) - 8 = 0 . Step 2 : Trying to factor by splitting the middle term. 2.1 Factoring 15x2-26x-8. The first term is, 15x2 its coefficient is 15 . The middle term is, -26x its coefficient is -26 . The last term, "the constant", is -8.
To find roots of the quadratic equation using quadratic formula, first convert the given quadratic equation into integers when the coefficients are fractions (Skip this step when coefficients are integers).
