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prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx
What is the answer to 4/3 =-6e-5/3 ? The answer to 4/3 =-6e-5/3 is e=-1/2; Solve for e: 4/3 =-6e-5/3; The solution is e=-1/2
Click here 👆 to get an answer to your question ️ Solve for e. 4/3 =-6e- 5/3.
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First, let's isolate the term with @$ e @$ on one side of the equation: @$ 4/3 + 5/3 = -6e @$ This simplifies to: @$ 3 = -6e @$ Finally, solve for @$ e @$ by dividing both sides by -6: @$ e = -3/6 @$ So, @$ \boldsymbol {e = -0.5} @$.
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