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Factor x^2-64. x2 − 64 x 2 - 64. Rewrite 64 64 as 82 8 2. x2 − 82 x 2 - 8 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b) where a = x a = x and b = 8 b = 8.
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- Solve by Factoring x^2-64=0
Solve by Factoring x^2-64=0. x2 − 64 = 0 x 2 - 64 = 0....
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x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)
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Rewrite x^{2}-64 as x^{2}-8^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
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Solve by Factoring x^2-64=0. x2 − 64 = 0 x 2 - 64 = 0. Rewrite 64 64 as 82 8 2. x2 − 82 = 0 x 2 - 8 2 = 0. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b) where a = x a = x and b = 8 b = 8. (x+8)(x− 8) = 0 (x + 8) (x - 8) = 0.
Learn how to solve polynomial factorization problems step by step online. Factor the expression x^2-64. Simplify \sqrt {x^2} using the power of a power property: \left (a^m\right)^n=a^ {m\cdot n}. In the expression, m equals 2 and n equals \frac {1} {2}. Calculate the power \sqrt {64}.
