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  1. SELECT T1.ID, T1.AccountNumber, T1.Date, MIN(T2.Date) AS Date2, DATEDIFF("D", T1.Date, MIN(T2.Date)) AS DaysDiff FROM YourTable T1 LEFT JOIN YourTable T2 ON T1.AccountNumber = T2.Accountnumber AND T2.Date > T1.Date GROUP BY T1.ID, T1.AccountNumber, T1.Date;

  2. 30 gru 2022 · Transact-SQL reference for the DATEDIFF function. Returns the numerical difference between a start and end date based on datepart.

  3. To calculate the difference between two dates in years, months, weeks, etc., you use the DATEDIFF() function: DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. date_part is the part of date e.g., a year, a ...

  4. 23 wrz 2023 · To calculate the difference between two dates in T-SQL, you’ll need to use the DATEDIFF function. This built-in function allows you to easily subtract one date from another and return the difference.

  5. 23 wrz 2023 · This built-in SQL function allows you to calculate the difference between two datetimes. It’s as simple as DATEDIFF (datepart, startdate, enddate). The datepart could be year, quarter, month, day and so on. SELECT DATEDIFF (day,'2022-01-01','2022-12-31') AS DiffDate.

  6. The DATEDIFF function returns the difference between two dates according to the datepart specified: such as year, day, month, etc. Syntax. DATEDIFF(datepart, date1, date2) Parameters. datepart - This is the datepart to get the difference between the two dates.

  7. 25 sie 2011 · The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF (interval, date1, date2) Parameter Values. Technical Details. More Examples. Example. Return the difference between two date values, in months: SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself » Example.