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You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365.2425): datediff(day,{start-date},{end-date},) / 365.2425. For instance, select datediff(day,'1 Jan 2000' ,'18 April 2014') / 365.2425.
30 gru 2022 · Transact-SQL reference for the DATEDIFF function. Returns the numerical difference between a start and end date based on datepart.
To calculate the difference between two dates in years, months, weeks, etc., you use the DATEDIFF() function: DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date.
7 paź 2024 · How to Perform SQL Server Date Diff. In SQL Server, there is only one recommended way to get the time between two date values. This is the DATEDIFF function, which has the following syntax: 1 DATEDIFF(datepart, startdate, enddate) The parameters accepted by this SQL Server function are: datepart: The units of time in which to get the difference ...
22 sty 2010 · It's gives you difference between two dates in Year. Here (2017-2011)=6 as a result. Syntax: DATEDIFF(interval, date1, date2)
25 sie 2011 · The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF (interval, date1, date2) Parameter Values. Technical Details. More Examples. Example. Return the difference between two date values, in months: SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself » Example.
The DATEDIFF function returns the difference between two dates according to the datepart specified: such as year, day, month, etc. Syntax DATEDIFF(datepart, date1, date2)
