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If you don't mind importing the json module, then the best way to handle it is through json.JSONDecodeError (or json.decoder.JSONDecodeError as they are the same) as using default errors like ValueError could catch also other exceptions not necessarily connected to the json decode one.
Try r.text instead of r.json()..., and then do whatever you want from there. If you are not sure the type of content it returns: h = requests.head('https://www.instagram.com/p/CJDxE7Yp5Oj/?__a=1') header = h.headers. contentType = header.get('content-type') print(contentType) Based on your URL, it returns text/html.
24 sie 2023 · Python JSONDecodeError. JSONDecodeError is an error that occurs when the JSON data is invalid, such as having missing or extra commas, missing brackets, or other syntax errors. This error is typically raised by the json.loads () function when it’s unable to parse the JSON data.
1 lut 2023 · A JSONDecodeError: Expecting value: line 1 column 1 (char 0) when running Python code means you are trying to decode an invalid JSON string. This error can happen in three different cases: Case 1: Decoding invalid JSON content Case 2: Loading an empty or invalid .json file Case 3: A request you made didn’t return a valid JSON
The loads() method is used to decode the JSON string into a Python dictionary. If the JSON content is invalid, you’ll receive the JSONDecodeError: Expecting value error, as shown in this example:
8 kwi 2024 · The Python "json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)" occurs when we try to parse something that is not valid JSON as if it were. To solve the error, make sure the response or the file is not empty, or conditionally check for the content type before parsing.
In this tutorial, you will learn to parse, read and write JSON in Python with the help of examples. Also, you will learn to convert JSON to dict and pretty print it.
