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  1. stackoverflow.com › questions › 2533890How to get an age from a D.O.B field in MySQL? - Stack Overflow

    select DATEDIFF(customer.dob, '2010-01-01') / 365.25 as age. will firstly yield a negative result (the arguments to DATEDIFF are in the wrong order), and secondly will produce inaccurate results for some dates, e.g.: SELECT DATEDIFF('2010-05-11','1984-05-11') / 365.25 AS age. produces the result:

  2. stackoverflow.com › questions › 2177543MySQL - Using If Then Else in MySQL UPDATE or SELECT Queries

    1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL

  3. stackoverflow.com › questions › 1262786MySQL - UPDATE query based on SELECT Query - Stack Overflow

    You can actually do this one of two ways: MySQL update join syntax: UPDATE tableA a. INNER JOIN tableB b ON a.name_a = b.name_b.

  4. dirask.com › posts › MySQL-UPDATE-query-with-IF-condition-conditional-update-pOv4JDMySQL - UPDATE query with IF condition (conditional update)

    In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:

  5. dba.stackexchange.com › questions › 305706MySQL - Update column based on multiple conditions

    6 sty 2022 · SELECT case_id, cat, birth, c_type, CASE -- 1st section: WHEN (COUNT(case_id) OVER (PARTITION BY case_id)) = 1 THEN CASE WHEN (DATEDIFF(NOW(), birth) / 365.25) >= 21 THEN 'SINGLE_PERSON' ELSE 'UNKNOWN' END -- 2nd section: WHEN COUNT(case_id) OVER (PARTITION BY case_id) = 2 AND SUM(CASE WHEN cat = 'WIFE' THEN 1 ELSE 0 END) OVER (PARTITION BY ...

  6. dba.stackexchange.com › questions › 148823mysql - return age in years and months from date of birth -...

    5 wrz 2016 · Is it possible to get the from_days (datediff (now (), user_birthdate)) factored into a single call without a nested query? user_id, year(from_days(datediff(now(), user_birthdate))) as years, month(from_days(datediff(now(), user_birthdate))) as months.

  7. dev.mysql.com › doc › refmanMySQL :: MySQL 8.2 Reference Manual :: B.3.4.2 Problems Using ...

    You should use this format in UPDATE expressions and in the WHERE clause of SELECT statements. For example: SELECT * FROM t1 WHERE date >= '2003-05-05'; As a convenience, MySQL automatically converts a date to a number if the date is used in numeric context and vice versa.

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