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Rectangle[{xmin, ymin}, {xmax, ymax}] represents an axis-aligned filled rectangle from {xmin, ymin} to {xmax, ymax}. Rectangle[{xmin, ymin}] corresponds to a unit square with its bottom-left corner at {xmin, ymin}.
- BoundaryMeshRegion
BoundaryMeshRegion - Rectangle—Wolfram Language...
- CanonicalizePolygon
CanonicalizePolygon[poly] gives a canonical representation...
- RoundingRadius
RoundingRadius - Rectangle—Wolfram Language Documentation
- BoundingRegion
Optimal bounding regions typically minimize some property...
- Cuboid
Cuboid is also known as interval, rectangle, square, cube,...
- Raster
Scaled and Offset can be used to specify the coordinates for...
- BoundaryMeshRegion
I feel the main difference is the style of programming that both languages invite you to do. Matlab is an imperative, procedural language; whereas Mathematica is a language which supports both imperative and declarative programming, but is mostly an (impure) functional language.
area = rectint(A,B) returns the area of intersection of the rectangles specified by position vectors A and B. If A and B each specify one rectangle, the output area is a scalar. A and B can also be matrices, where each row is a position vector.
18 wrz 2022 · Matlab is good in making functions but Mathematica is good for calculus and equation. Matlab can’t be a scientific calculator whereas Mathematica is good for being a scientific calculator. Mathematica is fast to do symbolic calculations as compared to Matlab.
Specify the values between 0 (no curvature) and 1 (maximum curvature). For example, a value of [0 0] creates a rectangle with square edges and value of [1 1] creates an ellipse. To use the same curvature for the horizontal and vertical edges, specify a scalar value between 0 and 1, inclusive.
2 paź 2011 · Based on Raskolnikov's answer here, one can build an implicit Cartesian equation for a $2p \times 2q$ rectangle: $$\left (\frac {x} {p}\right)^2+\left (\frac {y} {q}\right)^2=\sec\left (\arctan\left (\frac {x} {p},\frac {y} {q}\right)-\frac {\pi} {2}\left\lfloor\frac2 {\pi}\arctan\left (\frac {x} {p},\frac {y} ...
Syntax. a = polyarea(x,y) a = polyarea(x,y,dim) Description. a = polyarea(x,y) returns the area of the 2-D polygon defined by the vertices in vectors x and y. If x and y are vectors of the same length, then polyarea returns the scalar area of the polygon defined by x and y.
