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2 lut 2012 · or. if FreqSec (1,r+1) > FreqSec (r)*1.01 || FreqSec (1,r+1) <FreqSec (r)*0.99. The first of these is more general. The second of these, , is the short-circuiting OR that does not bother to evaluate the second expression if it already knows the final result after the first operation.
- or - Find logical OR - MATLAB - MathWorks
This MATLAB function performs a logical OR of inputs A and B...
- or - Logical OR for symbolic expressions - MATLAB - MathWorks
Syntax. A | B. or(A,B) Description. A | B represents the...
- If condition with multiple OR statements - MATLAB Answers - MathWorks
If condition with multiple OR statements. I would like to...
- or - Find logical OR - MATLAB - MathWorks
This MATLAB function performs a logical OR of inputs A and B and returns an array or a table containing elements set to either logical 1 (true) or logical 0 (false).
Syntax. A | B. or(A,B) Description. A | B represents the logical OR. A | B is true when either A or B is true, or when both A and B are true. example. or(A,B) is equivalent to A | B. Examples. collapse all. Set Assumption Using OR. Combine these symbolic inequalities into a logical condition by using |. syms x y. xy = x>=0 | y>=0;
any(a==solutions); The a==solutions line creates a matrix the same size as solutions, which contains 1's in indecies which where the conditional is true, and 0's where it is false. A few more examples: any(isprime([17:24])); %returns true; 17, 19 and 23 are prime.
10 lip 2020 · If condition with multiple OR statements. I would like to understand what's the problem here. PURPOSE: Not print 'd', if the multiple OR statements are satisfied. if (d ~= 1 || d ~= 3 ||d ~= 7 ||d ~= 9 ||... So that only cases that d = 2, 4, 5, 6, 8 are printed.
If statement with or condition. Learn more about matlab MATLAB. Hi given the following code BDR= [175 175 175 175 175 175 175 175 175 175 175 175 175]; SETTIMANA=[190 130 120 140 100 160 175 165 157 140 130 175 140 ]; NEXTpro = [25 60 50 40 30 30 30 35 10 34... Skip to content.
4 maj 2018 · As referenced in Ander's answer, the | operator is using short circuiting to skip evaluation of the second condition if the first is false (or empty). Some quick debugging will give you better understanding if we ignore short-circuiting:
