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The realloc() function returns a pointer to the newly allocated memory, which is suitably aligned for any kind of variable and may be different from ptr, or NULL if the request fails. If size was equal to 0, either NULL or a pointer suitable to be passed to free () is returned.
man realloc (1): The realloc() function shall change the size of the memory object pointed to by ptr to the size specified by size. The contents of the object shall remain unchanged up to the lesser of the new and old sizes.
The realloc () function shall deallocate the old object pointed to by ptr and return a pointer to a new object that has the size specified by size. The contents of the new object shall be the same as that of the old object prior to deallocation, up to the lesser of the new and old sizes.
6 lut 2012 · From what I can tell, it's as though relloc() frees the memory but does not free the virtual address space associated with the memory. As a result, malloc() will eventually fail. Here's a small console app that demonstrates the problem:
calloc, malloc, free, realloc - przydziela i zwalnia pamięć dynamiczną. SKŁADNIA¶ #include <stdlib.h> void *calloc(size_t nmemb, size_t size); void *malloc(size_t size); void free(void *ptr); void *realloc(void *ptr, size_t size); OPIS¶ Uwaga! To tłumaczenie może być nieaktualne!
The realloc() function returns a pointer to the newly allocated memory, which is suitably aligned for any built-in type and may be different from ptr, or NULL if the request fails. If size was equal to 0, either NULL or a pointer suitable to be passed to free () is returned.
The realloc() function changes the size of the memory block pointed to by ptr to size bytes. The contents of the memory will be unchanged in the range from the start of the region up to the minimum of the old and new sizes.
