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14 sty 2016 · Tangent to the x-axis means: Touching the x-axis, so the distance from the center is the radius. Having the distance from it center is equal to the height (y). Therefore, ρ = 3. The equation of the circle becomes: (x −2)2 + (x − 3)2 = 32. (x −2)2 + (x − 3)2 = 9. Answer link.
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Let $(x+3)^2 + (y+5)^2 = r^2$ be the equation of the circle with center $C = (-3,-5)$ and radius equal to $r$. Rewrite the tangent line's equation as: $y + 5 = \dfrac{29 - 12x}{5}$, substituting this $y$ into the equation of the circle and get: $(x+3)^2 + \dfrac{(29 -12x)^2}{25} - r^2 = 0 \iff 169x^2 - 546x + 1066 - 25r^2 = 0$.
Here we have to find the equation of the circle centered at (2,3) and touches x- axis.
Explanation. 1 Identify the center of the circle, given as (x_ {0}, y_ {0}) = (15, -7) (x0,y0)=(15,−7) 2 Determine the radius. The circle is tangent to the line y=-10 y =−10, so the radius is the distance from the center to the line.
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You can put this solution on YOUR website! with centre C (2 ; 3) and which is tangent to the x-axis. since the circle is tangent to the x-axis. the radius will be 3 units (y coordinate of the centre) now the equation of the circle with center (x1,y1) and radius r is. (x-x1)^2 + (y-y1)^2 = r^2. so the eq. is. if we expand we get.
