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  1. 13 lip 2016 · When you save some data using JSON.stringify() and then need to read that in php. The following code worked for me. json_decode( html_entity_decode( stripslashes ($jsonString ) ) );

  2. 27 sty 2016 · Probably the magic quotes screw up your JSON string and PHP doesn't recognize it anymore. Use stripslashes() before you hand it over to json_decode() : $a = json_decode(stripslashes($_POST['json'])); var_dump($a);

  3. 31 sty 2019 · This is the reverse process of the above section. JavaScript supports this conversion by using its built-in JSON.stringify method. This section lets us see an example code to learn how to use JSON.stringify with JavaScript.

  4. www.w3schools.com › js › js_json_phpJSON PHP - W3Schools

    PHP File explained: Convert the request into an object, using the PHP function json_decode (). Access the database, and fill an array with the requested data. Add the array to an object, and return the object as JSON using the json_encode () function.

  5. Returns a string containing the JSON representation of the supplied value. If the parameter is an array or object, it will be serialized recursively. If a value to be serialized is an object, then by default only publicly visible properties will be included.

  6. Returns the value encoded in json as an appropriate PHP type. Unquoted values true, false and null are returned as true, false and null respectively. null is returned if the json cannot be decoded or if the encoded data is deeper than the nesting limit.

  7. The json_decode () function is used to decode a JSON object into a PHP object or an associative array. Example. This example decodes JSON data into a PHP object: <?php. $jsonobj = ' {"Peter":35,"Ben":37,"Joe":43}'; var_dump (json_decode ($jsonobj)); ?> Run Example » The json_decode () function returns an object by default.

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