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1 A1 = F2 A2 Pascal’s Principle (Hydraulic Jack) A 1 d 1 = A 2 d 2 Hydraulic Jack F = Av Flow Rate A 1 v 1 = A 2 v 2 Continuity Equation P + ½ v 1 2 + gy = P 2 + ½ v 2 + gy ernoulli’s Equation GASES = F A Pressure p 1 V 1 = p 2 V 2 oyle’s Law V1 T1 = V2 T2 harles’ Law V1 n1 = V2 n2 Avogadro’s Principle p1V1 T1 = 2 V2 2 Combined Gas ...
We define a conductor as a material in which charges are free to move over macroscopic distances—i.e., they can leave their nuclei and move around the material. An insulator is anything else. In an insulator the charge distribution in an atom may change, but the charges do not leave their nuclei.
Set up for the class a model of an electric circuit, using wires, bulbs, and a battery. Demonstrate the properties of insulation and conductivity by testing several different materials.
Lecture begins with a recap of Gauss’s Law, its derivation, its limitation and its applications in deriving the electric field of several symmetric geometries—like the infinitely long wire. The electrical properties of conductors and insulators are discussed.
1. First use two wires to make a complete circuit with the battery and bulb. § Can you make the bulb light? What does that tell you? 2. Now open the circuit and use a third wire to insert an object into the circuit. § Based on your findings, classify the material or object as a conductor or insulator 3. Try attaching the clips to various ...
Fig. 1 shows the situation of an insulated wire. For NEC modeling, there are two radii of interest. One is the radius of the conducting wire (WR). The second is the radius of the wire-plus-insulation (SR). The difference in the two radii is the thickness of the insulation (D).
Let’s consider an insulated conductor. Earlier we have studied that whenever we place an excess amount of charge inside of a conducting medium, it immediately moves to the surface due to the Coulomb repulsive force and we end up with no net charge enclosed inside of the conducting medium.
