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Zadanie 1. Najpierw ustawiamy zmienną a na dowolną liczbę całkowitą, a następnie tworzymy instrukcję warunkową, która inaczej będzie reagowała na liczby podzielne przez trzy, a inaczej na inne liczby.
6 lut 2023 · For each trial (each time you draw 5 marbles) you need to keep count of how many are red and how many are green. If exactly 2 are red and 3 are green, increment your total counter.
Step by step solution. 01. Given information (Part a) A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $ 1.10; if they are different colors, then you win − $ 1.00. 02. Solution (Part b) Let, x = 1.1. p (1.1) = 5 2 10 2 + 5 2 10 2. So, P (1.
25 lip 2018 · A bag contains 10 red and 20 green marbles. Draw 5 without replacement. What is the probability of getting 2 red and 3 green?
26 kwi 2021 · Hint for A): How many red / blue / yellow marbles did you draw? $ 6 \times 7 \times 5 - 1 $ Hint for B): If you draw 5 marbles, then at least 2 of them must be the same color.
A bag contains 5 red marbles, 4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then a second marble is chosen. What is the probability that both marbles are green?
VIDEO ANSWER: The bag containing 5 red marbles that is n of R is equal to 5 blue marbles that is B is equal to 4 yellow marbles that is Y is equal to 3. We have to find out if the marble is blue or red.
