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HNO3 + Fe(OH)3 = Fe(NO3)3 + H2O is a Double Displacement (Metathesis) reaction where three moles of aqueous Nitric Acid [HNO 3] and one mole of solid Iron(Iii) Hydroxide [Fe(OH) 3] react to form one mole of aqueous Ferric Nitrate [Fe(NO 3) 3] and three moles of liquid Water [H 2 O]
Process: split the reaction into two half-reactions, balance the atoms and charges in each half-reaction, and then combine the half-reactions, ensuring that electrons are balanced. Example: Cu + HNO 3 = Cu(NO 3 ) 2 + NO 2 + H 2 O
Calculate the complete and net ionic equations, spectators and precipitates in Fe(OH)3(s) + 3HNO3(aq) = Fe(NO3)3(aq) + 3H2O(l)
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Step 1. Write down the unbalanced equation ('skeleton equation') of the chemical reaction. All reactants and products must be known. For a better result write the reaction in ionic form. Fe (NO 3) 2 + HNO 3 → Fe (NO 3) 3 + NO + H 2 O. Step 2. Separate the redox reaction into half-reactions.
Reaction between Ferric hydroxide and Nitric acid: Nitric acid reacts with basic metal hydroxides to form their respective nitrates. When Ferric hydroxide ( Fe ( OH ) 3 ) reacts with Nitric Acid ( HNO 3 ) , it will give Ferric nitrate ( Fe ( NO 3 ) 3 ) and water as a product.
To enter an ion, specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} = Fe{2+} + I2; Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but PhC2H5 + O2 = PhOH + CO2 + H2O will
