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Finding Factors. Factorizing algebraic expressions is a way of turning a sum of terms into a product of smaller ones. The product is a multiplication of the factors. Sometimes it helps to look at a simpler case before venturing into the abstract.
Example 1. Factor to get Prime Factors. 8x3 − 8. The terms have a common factor, both 8x3 and 8 are divisible by 8. We can rewrite the polynomial as 8(x3 − 1). Can the factors be factored anymore? Let’s repeat the process: (a) There are two terms in x3 − 1. Is it a diference of squares? No, since we have an x3 term. Is it a sum of two cubes?
Factoring Trinomials (a = 1) Date_____ Period____ Factor each completely. 1) b2 + 8b + 7 2) n2 − 11 n + 10 3) m2 + m − 90 4) n2 + 4n − 12 5) n2 − 10 n + 9 6) b2 + 16 b + 64 7) m2 + 2m − 24 8) x2 − 4x + 24 ... Free trial available at KutaSoftware.com. Title: Factoring 1
Factoring Trinomials (a > 1) Date_____ Period____ Factor each completely. 1) 3 p2 − 2p − ... Factor each completely. 1) 3 p2 − 2p − 5 (3p − 5)(p + 1) 2) 2n2 + 3n − 9 (2n − 3)(n + 3) ... Free trial available at KutaSoftware.com. Title: Factoring 2 Author:
Objective: Find the greatest common factor of a polynomial and factor it out of the expression. The inverse of multiplying polynomials together is factoring polynomials.
Unit 2 Polynomials 2.7 Factoring Perfect Square Trinomials Name_____ Date_____ Period____ ©X k2S0S1\4H hKtuqteaR oSEokfLtxwNaRrZep wLVLXCW.^ x cAYl^ld OrdiUghhjtVsL or_ehsKeTrwvCerdw. Factor each completely. 1) 3n2 + 30n + 75 3 (n + 5) 2 2) 9a2 - 30a + 25 (3a - 5) 2 3) r2 + 6r + 9 r + 3) 2 4) 25x2 - 40x + 16 (5x - 4 ...
Factoring Trinomials of the Form ax bx c2 -This method will work for every trinomial, whether the coefficient of the squared term is 1 or any other number; if the polynomial can be factored this will do it. The best way to explain the method is with the help of an example. Let’s factor 2 13 15xx2 .
