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  1. cuso4+fe=feso4+cu. Have a question about using Wolfram|Alpha? Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.

  2. Balancing step by step using the inspection method; Let's balance this equation using the inspection method. First, we set all coefficients to 1: 1 CuSO 4 + 1 Fe = 1 FeSO 4 + 1 Cu 2 For each element, we check if the number of atoms is balanced on both sides of the equation. Cu is not balanced: 1 atom in reagents and 2 atoms in products.

  3. www.symbolab.com › solver › step-by-stepFe+CuSO4 - Symbolab

    Pythagorean Theorem Calculator Circle Area Calculator Isosceles Triangle Calculator Triangles ... Roman Numerals Radical to Exponent Exponent to Radical To Fraction To Decimal To Mixed Number To Improper Fraction Radians to Degrees Degrees to Radians Hexadecimal Scientific Notation ... step-by-step. Fe + CuSO4 . en. Related Symbolab blog posts ...

  4. CuSO4 + Fe = Cu2 + FeSO4 is a Single Displacement (Substitution) reaction where two moles of aqueous Cupric Sulfate [CuSO 4] and two moles of solid Iron [Fe] react to form one mole of solid Dinuclear Copper Ion [Cu 2] and two moles of aqueous Iron(Ii) Sulfate [FeSO 4]

  5. CuSO4 + Fe = Cu + FeSO4 is a Single Displacement (Substitution) reaction where one mole of aqueous Cupric Sulfate [CuSO 4] and one mole of solid Iron [Fe] react to form one mole of solid Copper [Cu] and one mole of aqueous Iron(Ii) Sulfate [FeSO 4]

  6. Step 1/5 1. Identify the reactants and products: Reactants: Iron (Fe) and Copper sulfate (CuSO4) Products: Iron sulfate (FeSO4) and Copper (Cu) Step 2/5 2. Determine the oxidation states of each element: Fe: 0 → +2 Cu: +2 → 0 S: +6 → +4 Step 3/5 3. Balance the equation: Fe + CuSO4FeSO4 + Cu Step 4/5 4.

  7. Balancing step by step using the inspection method. Let's balance this equation using the inspection method. First, we set all coefficients to 1: 1 Fe + 1 CuSO 4 = 1 Cu + 1 Fe 2 (SO 4) 3. For each element, we check if the number of atoms is balanced on both sides of the equation.

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