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Nghi N. May 13, 2015 Replace cos 2x by \displaystyle{\left({2}{{\cos}^{{2}}{x}}-{1}\right)} f(x) = 2 + 3(2cos^2 x - 1) - cos x = 0. Call cos x = t. 6t^2 - t - 1 = 0. Solve by the ...
Rozwiąż równanie w przedziale . Skorzystamy ze wzoru na cosinus sumy. Szkicujemy cosinusa. Z wykresu widać, że. Skorzystamy ze wzoru. Szkicujemy tangensa. Z wykresu łatwo odczytać, że jedynym rozwiązaniem jest (bo ). Jeżeli natomiast , to możemy obie strony równania podzielić przez i otrzymujemy równanie. Szkicujemy sinusa.
Domi: Czyli 2x= π2 +kπ? 5-latek: OKres podstawowy y=cos (x) wynosi 2π. Teraz sprawdz ile jest rozwiazan w jednym okresie (czy tylko jedno ?
First, find out what the identities are for cos3θ and cos2θ in terms of cosθ. It looks like you know how to factorise - that ... Use the identity \cos^2 (x)=\frac {1+\cos (2x)} {2}. You should then be able to solve this for x by way of the inverse. Use the identity cos2(x)= 21+cos(2x).
Take the specified root of both sides of the equation to eliminate the exponent on the left side. cos(x) = ±√3 4 cos (x) = ± 3 4. Simplify ±√3 4 ± 3 4. Tap for more steps... cos(x) = ± √3 2 cos (x) = ± 3 2. The complete solution is the result of both the positive and negative portions of the solution. Tap for more steps...
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