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Locate the position of center of mass of the two point masses (i) from the origin and (ii) from 3 kg mass. Solution. Let us take, m1 = 3 kg and m2= 5 kg. (i) To find center of mass from the origin: The point masses are at positions, x1 = 4 m, x2 = 8 m from the origin along X axis. The center of mass xCM can be obtained using equation 5.4.
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Question 1 (**) Four particles A, B, C and D have masses 1kg, 2kg, 3kg and 4kg, respectively. The respective coordinates of the particles A, B, C and D are (2,3), (4,0), (−1,5) and (− −3, 4). a) Find the coordinates of the centre of mass of this system of four particles.
Explain why the centre of mass of the lamina lies on PQ. Find the distance of the centre of mass of the lamina from AB. Answer all questions. A hot air balloon moves vertically upwards with a constant velocity. When the balloon is at. height of 30 metres above ground level, a box of mass 5 kg is released from the balloon.
Answer. We know that center of mass will move under the action of force of gravity So $\mathbf{r_c}=\mathbf{v_c}t+\frac{1}{2}\mathbf{g}t^2$ Or $\mathbf{r_c}=\frac{m_1\mathbf{v_1}+m_2\mathbf{v_2}}{m_1+m_2}t+\frac{1}{2}\mathbf{g}t^2$ Multiple Choice Questions Question 23 Two masses m 1 and m 2 separated by thin rod of length L.
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a. Determine the coordinate of the center of mass for the three people, assuming x = 0 is where the 70 kg person is standing. b. The person of mass 82 kg starts sprinting to the right at a speed of 3 m/s. Find the velocity of the center of mass. c. Assume now that at the exact same time the 82 kg person starts running, the 70 kg person starts
