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  1. We make a clumsy factorial using the integers in decreasing order by swapping out the multiply operations for a fixed rotation of operations with multiply '*', divide '/', add '+', and subtract '-' in this order. * For example, clumsy (10) = 10 * 9 / 8 + 7 - 6 * 5 / 4 + 3 - 2 * 1.

  2. 4 paź 2024 · 2. Problem: One day Anindya was experimenting with factorials. Anindya wanted to express 10! 10! as the sum of factorial of some numbers in such a way that each number used is less than 10 10. The factorial of the same number can be used more than once.

  3. Suppose we want to calculate the clumsy factorial for N = 4. The series of operations will start at 4 and include the next integers in descending order applying multiplication (*), division (/), addition (+), and subtraction (-) in a repeating cycle until we reach 1.

  4. Factorial Trailing Zeroes - Given an integer n, return the number of trailing zeroes in n!. Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1. Example 1: Input: n = 3 Output: 0 Explanation: 3! = 6, no trailing zero.

  5. For example, factorial(10) = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1. We instead make a clumsy factorial: using the integers in decreasing order, we swap out the multiply operations for a fixed rotation of operations: multiply (*), divide (/), add (+) and subtract (-) in this order.

  6. class Solution {public int clumsy (int n) {if (n == 1) return 1; if (n == 2) return 2; if (n == 3) return 6; if (n == 4) return 7; if (n % 4 == 1) return n + 2; if (n % 4 == 2) return n + 2; if (n % 4 == 3) return n-1; return n + 1;}}

  7. 1 wrz 2018 · We make a clumsy factorial using the integers in decreasing order by swapping out the multiply operations for a fixed rotation of operations with multiply '*', divide '/', add '+', and subtract '-' in this order. For example, clumsy(10) = 10 * 9 / 8 + 7 - 6 * 5 / 4 + 3 - 2 * 1.

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