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Indefinite integral. Step-by-step solution. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.
x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)
17 mar 2016 · Answer link. tanx+C Note that 1/cosx=secx. Thus, int1/cos^2xdx=intsec^2xdx. This is a common integral: intsec^2xdx=tanx+C.
6 gru 2021 · $\int \frac {1}{\cos^2 x}\,dx=\int \sec^2 x=\tan x +c$ based directly on the list of immediate integrals. The other day a student asked me if we can evaluate the integral using a method like integration by substitution or integration by parts.
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What is the integral of 1/(cos^2(θ)) ? The integral of 1/(cos^2(θ)) is tan(θ)+C
Series expansion of the integral at x=0. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music….
