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5x 3 + 40y 6 = 5 • (x 3 + 8y 6) Trying to factor as a Sum of Cubes : 4.2 Factoring: x 3 + 8y 6 Theory : A sum of two perfect cubes, a 3 + b 3 can be factored into : (a+b) • (a 2-ab+b 2) Proof : (a+b) • (a 2-ab+b 2) = a 3-a 2 b + ab 2 + ba 2-b 2 a + b 3 = a 3 +(a 2 b-ba 2)+(ab 2-b 2 a)+ b 3 = a 3 + 0 + 0 + b 3 = a 3 + b 3 Check : 8 is the ...
18 maj 2015 · Using the above formula for a = x and b = 2y2 and factoring out constant 5, we get: 5x3 + 40y6 = 5x3 +5(2y2)3 = 5(x + 2y2)(x2 − 2xy2 +4y4)) Answer link. You can use a formula for a sum of cubes: a^3+b^3= (a+b)* (a^2-ab+b^2) Notice that 40y^6=5*8*y^6=5*2^3* (y^2)^3=5* (2y^2)^3 Using the above formula for a=x and b=2y^2 and factoring out ...
What is factor 5x^3+40y^6 ? The solution to factor 5x^3+40y^6 is 5(x+2y^2)(x^2-2xy^2+4y^4)
Solution. Lydia. Mechanical engineer · Tutor for 4 years. Answer: 5 (x+2y^ {2}) (x^ {2}-2xy^ {2}-4y^ {4}) 5(x+2y2)(x2−2xy2 −4y4) . Explanation: Factor the expression: 5 (x^ {3}-8y^ {0}) 5(x3−8y0) Rewrite the expression into the form of a^ {3}1b^ {3}-b^ {3} a31b3−b3 I 5 (x^ {3}- (2y^ {2})^ {3}) 5(x3−(2y2)3) Factor the expression using ...
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