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A projectile moves along its path with a constant horizontal velocity. But its vertical velocity changes by -9.8 m/s each second of motion.
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The time for projectile motion is completely determined by the vertical motion. So any projectile that has an initial vertical velocity of 14.3 m / s 14.3 m / s and lands 20.0 m below its starting altitude will spend 3.96 s in the air.
The time a projectile is in the air is governed by its vertical motion alone. Thus, we solve for t first. While the ball is rising and falling vertically, the horizontal motion continues at a constant velocity.
26 maj 2019 · The vertical component of velocity undergoes an acceleration of $g$ downwards whereas the horizontal component of velocity is constant. The distance traveled horizontally by the projectile depends on the horizontal speed of the projectile and the time that the projectile is in the air (time of flight).
The horizontal velocity remains constant, but the vertical velocity varies linearly, because the acceleration is constant. At any time, \(\mathrm{t}\), the velocity is: \[\begin{align} \mathrm{u_x} & \mathrm{=u⋅ \cos θ} \\ \mathrm{u_y} & \mathrm{=u⋅ \sin θ−g⋅t} \end{align}\]
The vertical velocity changes by -9.8 m/s each second of motion. On the other hand, the horizontal acceleration is 0 m/s/s and the projectile continues with a constant horizontal velocity throughout its entire trajectory.
An object’s horizontal position, velocity, or acceleration does not affect its vertical position, velocity, or acceleration. These motions can only be related by the time variable t . It is easy to forget that horizontal motion has constant velocity (and zero acceleration!) while vertical motion has constant acceleration.
