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  1. 10 lip 2012 · The DATEDIFF function is use to calculate the number of days between the required date. Example if you are diff current date from given date in string format. SELECT * , DATEDIFF (CURDATE (),STR_TO_DATE ('01/11/2017', '%m/%d/%Y')) AS days FROM consignments WHERE code = '1610000154'.

  2. 26 paź 2015 · PRINT DATEDIFF (DAY, '1/1/2011', '3/1/2011') will give you what you're after. This gives the number of times the midnight boundary is crossed between the two dates. You may decide to need to add one to this if you're including both dates in the count - or subtract one if you don't want to include either date. answered May 20, 2011 at 6:03.

  3. 25 sie 2011 · Example. Return the difference between two date values, in years: SELECT DATEDIFF (year, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself » Definition and Usage. The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF ( interval, date1, date2) Parameter Values. Technical Details. More Examples.

  4. The following example illustrates how to use the DATEDIFF() function to calculate the difference in hours between two DATETIME values: SELECT DATEDIFF ( hour , '2015-01-01 01:00:00' , '2015-01-01 03:00:00' ); Code language: SQL (Structured Query Language) ( sql )

  5. In this tutorial, you will learn how to use SQL Server DATEDIFF() function to calculate the number of years, months, weeks, days,etc., between two dates.

  6. 1 sty 2022 · Examples. For example, if you want to calculate the number of days between two dates, you can use the following SQL query: SELECT DATEDIFF(day, '2022-01-01', '2022-02-01') AS DayDiff; This query will return the number of days between January 1, 2022, and February 1, 2022, which is 31.

  7. 30 gru 2022 · This example calculates the number of day boundaries crossed between dates in two columns in a table. CREATE TABLE dbo.Duration (startDate datetime2, endDate datetime2); INSERT INTO dbo.Duration(startDate, endDate) VALUES ('2007-05-06 12:10:09', '2007-05-07 12:10:09'); SELECT DATEDIFF(day, startDate, endDate) AS 'Duration' FROM dbo.Duration ...

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