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Maximize or minimize a function with a constraint. Get the free "Lagrange Multipliers" widget for your website, blog, Wordpress, Blogger, or iGoogle. Find more Mathematics widgets in Wolfram|Alpha.
- RobertoFranco
Lagrange Multipliers. Added Nov 17, 2014 by RobertoFranco in...
- RobertoFranco
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To find the shortest distance from a point, (5, 0, 1) to a function z = x^2 + 3*y^2, using the Langrange multiplier. How is this done best? Is the function to be minimized the function f(x, y, z) = x^2 + y^2 + z^2? with the points inserted so that we get (x - 5)^2 + y^2 + (z-1)^2 ?
16 sty 2023 · The distance \(d\) from any point \((x, y)\) to the point \((1,2)\) is \[\nonumber d = \sqrt{ (x−1)^2 +(y−2)^2} ,\] and minimizing the distance is equivalent to minimizing the square of the distance.
I'm trying to use Lagrange multipliers to show that the distance from the point (2,0,-1) to the plane $3x-2y+8z-1=0$ is $\frac{3}{\sqrt{77}}$. Our professor gave us two hints: We want to minimize a function that describes the distance to (2,0,-1) subject to the constraint $g(x,y,z) = 3x-2y+8z-1=0$, and Compare this method to the equation for ...
5 maj 2023 · Use the method of Lagrange multipliers to find the minimum value of the function \[f(x,y,z)=x^2+y^2+z^2\] subject to the constraints \( 2x+y+2z=9\) and \(5x+5y+7z=29.\) Hint. Use the problem-solving strategy for the method of Lagrange multipliers with two constraints. Answer \(f(2,1,2)=9\) is a relative minimum of \(f\), subject to the given ...
7 lis 2017 · Using Lagrange multipliers find the distance from the point (1, 2, −1) ( 1, 2, − 1) to the plane given by the equation x − y + z = 3. x − y + z = 3. Langrange Multipliers let you find the maximum and/or minimum of a function given a function as a constraint on your input.