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  1. Integration by Parts To reverse the chain rule we have the method of u-substitution. To reverse the product rule we also have a method, called Integration by Parts. The formula is given by: Theorem (Integration by Parts Formula) ˆ f(x)g(x)dx = F(x)g(x) − ˆ F(x)g′(x)dx where F(x) is an anti-derivative of f(x).

  2. Integration by Parts. Name___________________________________. Date________________ Period____. Evaluate each indefinite integral using integration by parts. u and dv are provided. 1) ∫ x x e dx; u = x, dv = x e dx. 3) ∫ x x ⋅ 2 dx; u = x, dv = 2 dx. x.

  3. 3. Find the following integrals. The table above and the integration by parts formula will be helpful. (a) R xcosxdx (b) R lnxdx (c) R x2e2x dx (d) R ex sin2xdx (e) Z lnx x dx Additional Problems 1. (a) Use integration by parts to prove the reduction formula Z (lnx)n dx = x(lnx)n −n Z (lnx)n−1 dx (b) Evaluate R (lnx)3 dx 2.

  4. The presentation is structured as follows. You’re given an integral. You should try and solve it. If you struggle, then there’ll be a hint - usually an indication of the method you should use. Finally a full solution will be given. Tomasz Lechowski Batory 2IB A & A HL September 11, 2020 2 / 22

  5. Introduction to Differential Equations. Separable Equations. Exponential Growth and Decay. Free Calculus worksheets created with Infinite Calculus. Printable in convenient PDF format.

  6. We do integration by parts in the last integral with. u = cos x ) du = sin x dx dv = ex dx ) v. Z Z. ex sin x ex cos x dx = ex sin x (cos x) (ex) (ex) ( sin. Z. = ex sin x ex cos x ex sin x dx. x dx) We add the last integral on both sides. Z. ex sin x = ex sin x ex cos x ex sin x dx. Z ex sin x dx + ex sin x dx = ex sin x ex cos x ex sin x dx +.

  7. Integrals. Advanced Integration By Parts. 1. ∫xsin. ( x. ) cos. ( x. ) dx. 2. ∫xsin. ( 2x. ) cos. ( 3x. ) dx. 3. ∫. 2xsin. ( x. ) cos. 3 ( x. ) 4. ∫. x. dx. cos. 2 ( x. )

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