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2 dni temu · A sphere with radius \(r\) has a volume of \( \frac{4}{3} \pi r^3 \) and a surface area of \( 4 \pi r^2 \). A sphere has several interesting properties, one of which is that, of all shapes with the same surface area, the sphere has the largest volume.
- Thaddeus Abiy
Chętnie wyświetlilibyśmy opis, ale witryna, którą oglądasz,...
- Worranat Pakornrat
Chętnie wyświetlilibyśmy opis, ale witryna, którą oglądasz,...
- Thaddeus Abiy
3 dni temu · Total Surface Area of Hemisphere: \[ \text{Total Surface Area} = 3 \pi r^2 \] where \(r\) is the radius of the hemisphere, and \(\pi\) (Pi) approximates to 3.14159265359. Example Calculation. To calculate the properties of a hemisphere with a radius of 2 units: Volume: \[ \text{Volume} = \frac{2}{3} \pi (2)^3 = 33.5103216383 \text{ units}^3 \]
6 dni temu · The formula to calculate the density of a sphere involves the volume of a sphere and its mass: \ [ D = \frac {m} {\frac {4} {3}\pi r^3} \] where: \ (D\) is the density in kilograms per cubic meter (kg/m³), \ (m\) is the mass of the sphere in kilograms, \ (r\) is the radius of the sphere in meters. Example Calculation.
3 dni temu · The calculator utilizes integral calculus to determine the volume of an object based on the area of its cross-sections. The formulas for calculating volume depend on whether the object is revolved around the x-axis or the y-axis:
5 dni temu · The dome surface area (DSA) formula is an elegant expression of geometry and calculus: \ [ \text {DSA} = 2\pi rh \] where: \ (\pi\) is the constant Pi (\ (\approx 3.14159\)), \ (r\) is the dome radius, \ (h\) is the dome height.
1 dzień temu · Consider a sphere with a radius of \( 5.6 \mathrm{~m} \). Using the ALEKS calculator, approximate the volume of the sphere. To do the approximation, do not round any intermediate steps, and use the \( \pi \) button on the calculator. Round your answer to the nearest hundredth. If necessary, refer to the list of geometry formulas.
4 dni temu · The sphere of radius \(r\) is obtained by revolving \( C\) around the \( x\)-axis. The arc length \(L\) of \( C\) is just \( \pi r\) since it is half a circle. The centroid of \( C\) is on the \(y\)-axis by symmetry.
