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2 dni temu · \[ \omega_0^2 = \omega^2 \left( 1 - 2 k^2 \right) , \qquad \beta = \frac{2k^2 \omega^2}{c_1^2} \] which gives \[ \omega = \sqrt{\omega_0^2 + c_1^2 \beta} , \qquad k = \sqrt{\frac{c_1^2 \beta}{2 \left( \omega_0^2 + c_1^2 \beta \right)}} .
4 dni temu · Hypocycloid If the smaller circle has radius r, and the larger circle has radius R = kr, then the parametric equations for the curve can be given by either: \[ \begin{split} x(\theta ) &= \left( R-r \right) \cos \theta + r\,\cos \left( \frac{R-r}{r}\,\theta \right) , \\ y(\theta ) &= \left( R-r \right) \sin \theta - r\,\sin \left( \frac{R-r}{r ...
3 dni temu · If parameters μ n and μ k are chosen in a way to annihilate the right-hand side of Eq.\eqref{EqOrtho.2}, we get orthogonality of Bessel's functions. We consider three important cases of boundary conditions for which Bessel's functions are orthogonal.
2 godz. temu · The orthogonal projection of the point (2,-3) on the line x+y=0 isa) $\\left(-\\frac{1}{2}, \\frac{3}{2}\\right)$b) $(2,3)$c) $(-4,6)$d) $\\left(\\frac{5}{2}, \\fra...
3 dni temu · sigma=s, absolute_sigma=True. Parameters order of magnitude are alike, fitness is good: But this fit is very sensitive to noise and initial guess which is expected as it must solve a stiff ODE for each point of the curve. It also seems that multiple combination of parameters can lead to equivalent fitness.
3 dni temu · Given that the trajectory of a projectile is represented by \(\sqrt { 3 } x-\frac { g{ x }^{ 2 } }{ 2 },\) find the angle of projection in degrees.
2 dni temu · Given two points \( P \) and \( Q\) on the curve, define \( R=-(P+Q) \) to be the third point on the line through \( P \) and \( Q \) that intersects the curve. Note that \( R=P \) or \( R=Q \) is possible if the line is tangent to the curve at \( P \) or \( Q \), as in picture 2 in the diagram above.
