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1 dzień temu · Projectile Motion Use the result of Exercise 87 to determine the series for the path of a projectile launched from ground level at an angle of θ=60^∘, with a...
4 dni temu · Throughout 53° its flight, the horizontal component of the balloon's velocity _____. A) first decreases by 10 m/s each second, then increases by 10 m/s each second B) stays constant at 30 m/s C) stays constant at 40 m/s D) stays constant at 50 m/s
1 dzień temu · Enter the horizontal distance (change in x-direction) and the maximum height reached by the projectile. Calculate Velocity: Click the “Calculate Velocity” button to initiate the calculation. Result Display: The calculator computes the launch velocity based on the given parameters and displays the result. Application:
4 dni temu · A football in flight during a field goal. A soccer player kicks a soccer ball at +10 m/s at an angle of 60°. What are the horizontal and vertical components of velocity of the kick? Vx = +5.00 m/s and Vy = +8.66 m/s.
4 dni temu · The size of the total speed of the ball after 1 s = √ (10²+9.8²) = √196.04 ≈ 14.0 m/s. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Ignore air resistance and assume it takes 30 s for the engine to hit the ground. a) Show that the airplane is 4.5 km high.
5 dni temu · A projectile is fired vertically upward into the air, its position (in feet) above the ground after t seconds is given by the function s ( t). Use limits to determine the instantaneous velocity of the projectile at t = a seconds for the given value of a . s ( t) = − 16 t 2 + 60 t; a = 1.
5 dni temu · Time of maximum height is the time when the object attains the maximum height and is given by $t = \dfrac{{u\sin \theta }}{g}$. Time of flight is the total time taken by the object to cover the total horizontal distance or in other words the time till when the object is in air and is given by $T = \dfrac{{2u\sin \theta }}{g}$.
