Search results
5 dni temu · For point P, x 1 = 2, y 1 = 5, z 1 = 6. For point Q, x 2 = 3, y 2 = 4, z 2 = 7. Distance between P and Q is given as. PQ = √ [ (x 2 – x 1) 2 + (y 2 – y 1) 2 + (z 2 – z 1) 2] Now filling the values of coordinates in the above formula we get. PQ = √ [ (3 – 2) 2 + (4 – 5) 2 + (7 – 6) 2] ⇒ PQ = √ (1 + 1 + 1) = √3 units.
4 dni temu · Solution: As given points are X (5, 10) and Y (2, 4). So, the distance between them is using the formula is. D = \sqrt { { (5-2)}^2+ { (10-4)}^2} (5−2)2 +(10−4)2. ⇒ D = \sqrt { { (3)}^2+ { (6)}^2} (3)2+(6)2. ⇒ D = \sqrt {9+36} 9+36. ⇒ D = \sqrt {45} = 3\sqrt {5} 45 =3 5. So, the distance between X and Y is 3√5 units. Derivation for Distance Formula
2 dni temu · \begin {aligned} a=\dfrac { (\text {change in velocity})} { (\text {time period})}&=\dfrac {v-v_0} {t_2-t_1}\\ &=\dfrac {v-v_0} {\Delta t}\\ \Rightarrow v &= v_0 + a\Delta t . \end {aligned} a = (time period)(change in velocity) ⇒ v = t2 − t1v −v0 = Δtv −v0 = v0 +aΔt.
6 dni temu · Graphs and Tables (G&T) Facts: The graph refers to a plane's flight from one location to another. The vertical axis represents the distance, in kilometers, between the plane and its destination. The horizontal axis represents the time, t minutes, ...
2 dni temu · P (\text {catching the bus}) = \dfrac {\text {area of desired outcomes}} {\text {area of total outcomes}} = \frac {60^2 - \frac {55^2} {2}-\frac {40^2} {2}} {60^2} = \frac {103} {288} \approx 36\%.\ _\square P (catching the bus) = area of total outcomesarea of desired outcomes = 602602 − 2552 − 2402 = 288103 ≈ 36%.
4 dni temu · Horizontal stretching/shrinking changes the x x -values of points. Transformations that affect the x x -values are counter-intuitive. Vertical/horizontal stretching/shrinking usually changes the shape of a graph. The lesson Graphing Tools: Vertical and Horizontal Scaling in the Algebra II curriculum gives a thorough discussion of horizontal and ...
3 dni temu · After calculating the distance between two points, you get the speed if we know the time spent to journey from point A to the B. Enter the elapsed time in the format hh:mm:ss to get the average speed. If you know the ending point, and the average speed you can get the time to reach point B.
