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The distance between a point and a line, is defined as the shortest distance between a fixed point and any point on the line. It is the length of the line segment that is perpendicular to the line and passes through the point.
The equation of a plane perpendicular to the line is $$x+y+z=a.$$ If this plane passes through $(2,2,1)$ then $a=5$. So the plane $x+y+z=5$ intersects the line when $$3t+6=5$$ so $t=-\frac{1}{3}$ and now you just need the distance between $S$ and $(\frac{5}{3},\frac{5}{3}, \frac{5}{3})$.
Find the perpendicular distance from the point (5, 6) to the line −2x + 3y + 4 = 0. x-intercept p1 = [0, -4/3] y-intercept p2 = [2, 0] shortest distance from p3 = [5, 6] = 3.328
Shows how to find the perpendicular distance from a point to a line, and a proof of the formula.
The distance (or perpendicular distance) from a point to a line is the shortest distance from a fixed point to any point on a fixed infinite line in Euclidean geometry. It is the length of the line segment which joins the point to the line and is perpendicular to the line.
I need to show that the perpendicular distance from the point B (with position vector $\vec{b}$) to the straight line $\vec{r}$=$\vec{a} + \lambda\vec{l}$ is given by $\dfrac{\|(\vec{a-b})\times\...
Learn how to find the perpendicular distance of a point from a line easily with a formula. For the formula to work, the line must be written in the general form.
