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Problem #1: Sea water contains roughly 28.0 g of NaCl per liter. What is the molarity of sodium chloride in sea water? Solution: MV = grams / molar mass (x) (1.00 L) = 28.0 g / 58.443 g mol¯ 1. x = 0.4790993 M to three significant figures, 0.479 M
For the first five problems, you need to use the equation that says that the molarity of a solution is equal to the number of moles of solute divided by the number of liters of solution. In this problem, simply solve using the molarity equation to find that the concentration of the solution is 10 M.
MOLARITY (M) = moles of solute. Liters of solvent. MOLALITY (m or ) = moles of solute kg of solvent. Molarity Example: 4.0 moles of LiCl is dissolved in 5.0 liters of water. What is the molarity of the solution? 4.0 moles = 0.8 M This solution is 0.8 Molar or 0.8 M. 5.0 Liters.
When dealing with solutions, we measure out volumes instead of weighing out quantities. Volume is related to the number of moles present using the concentration or molarity. Concentration (symbol c) is defined as the number of moles of a substance dissolved in one litre of solution: = (mol) (L) Critical thinking questions. 1.
Calculate the molarity of each of the following solutions: (a) 0.195 g of cholesterol, C 27 H 46 O, in 0.100 L of serum, the average concentration of cholesterol in human serum. (b) 4.25 g of NH 3 in 0.500 L of solution, the concentration of NH 3 in household ammonia.
Calculate molarity by dissolving 25.0g NaOH in 325 mL of solution. Calculate grams of solute needed to prepare 225 mL of 0.400 M KBr solution. Calculate mL of 0.650M KNO 3 needed to contain 25.0g KNO 3 .
28 maj 2020 · Calculate the molarity of each of the following solutions: (a) 0.195 g of cholesterol, C 27 H 46 O, in 0.100 L of serum, the average concentration of cholesterol in human serum. (b) 4.25 g of NH 3 in 0.500 L of solution, the concentration of NH 3 in household ammonia.
