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12 lis 2014 · What you can do is use two variables to keep track of the position of each word and calculate the distance with a single pass through the list => O(N). int index1 = -1; int index2 = -1; int minDistance = Integer.MAX_VALUE; int tempDistance = 0; for (int x = 0; x < strings.length; x++) {.
30 wrz 2022 · The task is to return an array of distances representing the shortest distance from the character X to every other character in the string. Examples: for S [0] = ‘g’ nearest ‘e’ is at distance = 1 i.e. S [1] = ‘e’. similarly, for S [1] = ‘e’, distance = 0.
24 cze 2014 · Design and implement a Distance class that stores the distances between cities in a two-dimensional array. This class will need some way to map a city name, Boise, into an integer that can be used as an array subscript.
31 sty 2024 · Levenshtein distance is a measure of the similarity between two strings, which takes into account the number of insertion, deletion and substitution operations needed to transform one string into the other.
22 lis 2021 · Given 2 values and an array, I must return the minimal distance between the indices of both values, as efficiently as I can in terms of run time and space. This is my solution: public static int minDist (int[] a, int x, int y) { int index_one = a[0]; int index_two = a[0]; for(int i = 0 ; i < a.length ; i++) . if(a[i] == x) index_one = i;
5 paź 2013 · You need to substract rather than add to calculate distance between each one. So you need two for loops to get all combinations. Example: public static void main(String args[]){. int i =0; int j=0; double[] stations = {10,20,30}; for(i=0;i<stations.length;i++){. for(j=i+1;j<stations.length;j++){.
20 wrz 2015 · public class Main { /*Write a method to calculate the distance between two letters (A-Z, a-z, case insensitive). The input to the method is two char primitives. If either char is not A-Za-z, throw an AlphabetException.
