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  1. Distance Formula and Pythagorean Theorem Example: The distance between (3, 4) and (x, 7) is 5 units. Find x. Using the distance formula: (3 —x)2 + (4—7) x) 3 Solving Graphically (Pythagorean Theorem) Example: b b 3 -5 4 or -4 The length of segment AB is 20. If the coordinate of Ais (5, 1), and the coordinate of B is (-6, y), what is b?

  2. 2-1 Position, Displacement, and Distance In describing an object’s motion, we should first talk about position – where is the object? A position is a vector because it has both a magnitude and a direction: it is some distance from a

  3. Justification: In order to determine if Jordan escapes or is caught we must check if the distance between Jordan and the Lion reaches zero at a time before or after Jordan reaches the Land Rover. The first step in solving this problem is breaking it into two segments.

  4. “linear” quantities (distance s, speed v, tangential acceleration at) are related to the angular quantities (angle θ, angular speed ω, angular acceleration α) by a factor of r : s = r θ, v = r ω, a t = r α.

  5. Practice Equations of Lines: Slope, Distance, and Midpoint Formulas. Answer these problems, then check your answers using the key on the next page. If you missed something, look at the solutions after the answer key, and if you still don’t understand, watch the review video again. #1) Find the slope of the line passing through the points ( 4 ...

  6. Problems. Problem 1: Find the distance between the points (2, 3) and (0, 6). Problem 2: Find the distance between point (-1, -3) and the midpoint of the line segment joining (2, 4) and (4, 6). Problem 3: Find x so that the distance between the points (-2, -3) and (-3, x) is equal to 5.

  7. Answer: 1) 135 km, 85km forward 2) 0 m, 6 m • Distance ( ): the separation between two points. Ex, the length of an object. Usually measures in _____. No _____ needed ex) • Displacement ( or ): A measure of the change in position. Needs _____ Δd = final position – initial position.