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The same process can be used to convert problems with several units in them. Consider the following example. Example 1.6.2. A student averaged 45 miles per hour on a trip. What was the student’s speed in feet per second?
12 lip 2019 · Learn how to solve problems involving distance, rate, and time, and practice using the distance/rate/time formula.
12 wrz 2022 · First we calculate the average speed using the given units, then we can get the average speed into the desired units by picking the correct conversion factors and multiplying by them. The correct conversion factors are those that cancel the unwanted units and leave the desired units in their place.
First we calculate the average speed using the given units, then we can get the average speed into the desired units by picking the correct conversion factors and multiplying by them. The correct conversion factors are those that cancel the unwanted units and leave the desired units in their place.
A student averaged 45 miles/hour (mi/h) on a trip. What was the student’s speed in feet/second (ft/s)? [latex]\dfrac{45 mi}{hr} = 45\text{mi x}\dfrac{5280 ft}{1 mi}\times\dfrac{1 hr}{3600 s}[/latex] This will cancel the units of mi & hr, and leave ft & s [latex]45\dfrac{mi}{hr} = 45\times\dfrac{5280\text{ft}}{1 mi}\times\dfrac{1 hr}{3600 s ...
21 sie 2023 · For example, to convert from miles per hour to kilometers per hour you would multiply by 0.44704 then divide by 0.2777778. Or, multiply by 0.44704/0.27777778 = 1.6093439. So, to convert directly from mph to km/h (kph), you multiply by 1.6093439.
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