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What is factor 5x^3+40y^6 ? The solution to factor 5x^3+40y^6 is 5(x+2y^2)(x^2-2xy^2+4y^4)
Solution - Factoring binomials using the difference of squares. 5 ⋅ ( x + 2 y 2) ⋅ ( x 2 − 2 x y 2 + 4 y 4) Step by Step Solution. Step 1 : Equation at the end of step 1 : (5 • (x3)) + (23•5y6) Step 2 : Equation at the end of step 2 : 5x3 + (23•5y6) Step 3 : Step 4 : Pulling out like terms : 4.1 Pull out like factors :
Solution. Lydia. Mechanical engineer · Tutor for 4 years. Answer: 5 (x+2y^ {2}) (x^ {2}-2xy^ {2}-4y^ {4}) 5(x+2y2)(x2−2xy2 −4y4) .
18 maj 2015 · Notice that 40y6 = 5 ⋅ 8 ⋅ y6 = 5 ⋅ 23 ⋅ (y2)3 = 5 ⋅ (2y2)3. Using the above formula for a = x and b = 2y2 and factoring out constant 5, we get: 5x3 + 40y6 = 5x3 +5(2y2)3 = 5(x + 2y2)(x2 − 2xy2 +4y4)) Answer link.
You can put this solution on YOUR website! 5X^3+40Y^6 factor completely. ------ 5 (x^3 + 8y^6) --- = 5 (x^3 + (2y^2)^3) ---- = 5 (x + 2y) (x^2-x (2y)+ (2y)^2) ---- = 5 (x+2y) (x^2-2xy+4y^2) ============================= cheers, Stan H.
