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What is factor 5x^3+40y^6 ? The solution to factor 5x^3+40y^6 is 5(x+2y^2)(x^2-2xy^2+4y^4)
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18 maj 2015 · You can use a formula for a sum of cubes: a3 +b3 = (a +b) ⋅ (a2 − ab +b2) Notice that 40y6 = 5 ⋅ 8 ⋅ y6 = 5 ⋅ 23 ⋅ (y2)3 = 5 ⋅ (2y2)3. Using the above formula for a = x and b = 2y2 and factoring out constant 5, we get: 5x3 + 40y6 = 5x3 +5(2y2)3 = 5(x + 2y2)(x2 − 2xy2 +4y4)) Answer link.
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