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26 mar 2016 · After the hit, the players tangle up and move with the same final velocity. Therefore, the final momentum, p f, must equal the combined mass of the two players multiplied by their final velocity, (m 1 + m 2)v f, which gives you the following equation: (m 1 + m 2)v f = m 1 v i 1. Solving for v f gives you the equation for their final velocity:
15 gru 2023 · Calculate the final velocity after an inelastic collision. Solution: v' = (1.5 kg × 3 m/s + 2.0 kg × (-2 m/s)) / (1.5 kg + 2.0 kg) = 0.6 m/s. Numerical Problem: Two objects with masses of 0.8 kg and 1.2 kg are moving with initial velocities of 4 m/s and -3 m/s, respectively.
In this video, David solves an example elastic collision problem to find the final velocities using the easier/shortcut approach. Created by David SantoPietro.
20 lip 2022 · After the collision, particle 2 moves with an unknown speed \(v_{2, f}\) at an angle \(\theta_{2, f}=45^{\circ}\) with respect to the positive x-direction. (i) Determine the initial speed \(v_{2 i}\) of particle 2 and the final speed \(v_{2, f}\) of particle 2 in terms of \(\mathcal{V}_{1, i}\). (ii) Is the collision elastic?
20 lip 2022 · Equating the momentum components before and after the collision gives the relation \[m_{1} v_{1 x, i}+m_{2} v_{2 x, i}=m_{1} v_{1 x, f}+m_{2} v_{2 x, f} \nonumber \] Because the collision is elastic, kinetic energy is constant. Equating the kinetic energy before and after the collision gives the relation
We didn't know the velocity of either object after the collision, so we had to solve this expression for one of the velocities, and then plug that into conservation of kinetic energy, which we can do, because kinetic energy's conserved for an elastic collision.
5 lis 2020 · where \(\mathrm{v_1}\) is the initial velocity of the first mass, \(\mathrm{v_1′}\) is the final velocity of the first mass, \(\mathrm{v_2}\) is the initial velocity of the second mass, and \(\mathrm{θ_1′}\) is the angle between the velocity vector of the first mass and the x-axis.
