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  1. 8. The distance between two cities is 144 km, it takes me 3 hours to travel between these cities, determine my average speed. Calculate Distance = R̅× P 9. A whale swims at a constant speed of 8.0 m/s for 17 s. Calculate the distance travelled by the whale. 10. A girl cycles for 30s at a speed of 4 m/s. Calculate the distance she travels. 11.

  2. You have just derived the distance formula! Note that given any two points with coordinates (x1, y1) and (x2, y2), the distance, d (also called Euclidean distance), between them is given by the formula below. formula to compute the distance between the following points: 1. (1,1) and (3,7) 2. (-1,5) and (2,9)

  3. When you describe distance, you only include the magnitude, the size or amount, of the distance traveled. However, when you describe the displacement, you take into account both the magnitude of the change in position and the direction of movement.

  4. show your location at 10-second intervals, starting at t = 0. Using the graph in Figure 2.4, find (c) your net displacement and (d) the total distance you covered during the 50-second period. SOLUTION (a) At a time of t = 40 s, the graph shows that your motion changes from travel in the positive x-direction to travel in the negative x-direction.

  5. Force, Distance, and Work 1. What force acts on the object when it has been moved 4.0 m? 2. How far has the object been moved when the force on it is 200.0 N? 3. Explain the shape of the line on the graph. 4. Which formula is used to calculate work when a constant force is exerted on an object? 5.

  6. The distance travelled by the object is (6 + 1.5 + 4) = 11.5m. The displacement of the object is 6.5m to the right. Questions 1. Define “distance” 2. Define “displacement”. 3. Draw a diagram to show the difference between distance and displacement. 4. Which quantity is a vector quantity: distance or displacement? 5.

  7. The distance between two points P(x 1, y 1) and Q(x 2, y 2) is given by the formula . Proof: Draw PR and QS perpendicular to the x-axis. A perpendicular from the point P on QS is drawn to meet it at the point T. Then OR = x 1, OS = x 2, So, RS = x 2 – x 1 = PT. Also SQ = y 2, ST = PR = y1. So, QT = y 2 – y1. Now applying the Pythagoras ...