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Use the rearranged speed formula to calculate the distance. Distance $= Speed \times Time$ Distance $= 80\; mph \times 3\; hours = 240$ miles. Therefore, the train, when traveling at a constant speed of 80 miles for 3 hours, is 240 miles. 4. What is the time required by a car that travels a distance of 400 miles at a speed of 60 mph? Solution:
The formula speed = distance ÷ time can be rearranged, just like any other equation. The formula can be rearranged in three ways: speed = distance ÷ time. distance = speed × time.
t = 10 min. t = 10min × 60s/1min. t = 600 s. The speed of the cart and the time are certainly available. Therefore, one can find the distance by using the formula: d = st. d = (7.5 m/s) (600 s) d = 4500 m. Hence, the distance which the golf cart traveled is 4500 m, which is definitely equal to 4.5.
Solution: Given: Distance Covered d = 80 miles, Time taken, t = 4 hours. Speed is calculated using the formula: x = d/t. = 80/4. = 20 miles/hr. Question 3: In a cycle race, a cyclist is moving with a speed of 2 km/hr. He has to cover a distance of 5 km. Calculate the time will he need to reach his destiny? Solution:
4 dni temu · The formula to calculate time, when speed and distance are given is: Time = Distance Speed T i m e = D i s t a n c e S p e e d. Time taken by car to cover 160 miles is : Time = 160 40 T i m e = 160 40. T = 4 hours. Hence, a boy will take 4 hours to cover a distance of 160 miles at a speed of 40 miles per hour.
To find distance, speed is beside time, so distance is speed multiplied by time. , , , , s = speed (meters/second) d = distance traveled (meters) t = time (seconds) Distance Speed Time Formula Questions: 1) A dog runs from one side of a park to the other. The park is 80.0 meters across.
If we know three of these five kinematic variables for an object undergoing constant acceleration, we can use a kinematic equation to solve for one of the unknown variables. The kinematic equations are listed below. 1. v = v 0 + a t. 2. Δ x = ( v + v 0 2) t. 3. Δ x = v 0 t + 1 2 a t 2. 4. v 2 = v 0 2 + 2 a Δ x.
